3k^2=5k+7

Solution for 3k^2=5k+7 equation:

3k^2=5k+7

We move all terms to the left:

3k^2-(5k+7)=0

We get rid of parentheses

3k^2-5k-7=0

a = 3; b = -5; c = -7;
Δ = b2-4ac
Δ = -52-4·3·(-7)
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{109}}{2*3}=\frac{5-\sqrt{109}}{6}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{109}}{2*3}=\frac{5+\sqrt{109}}{6}
$